What is the derivative of (2x-x^2^2+9) ?

The derivative of (2x-x^2^2+9) is 2(-2x+2)(-x^2+2x)

What is the first derivative of (2x-x^2^2+9) ?

The first derivative of (2x-x^2^2+9) is 2(-2x+2)(-x^2+2x)

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\frac{d}{d x} ((2 x - x^{2})^{2} + 9)

2 (- 2 x + 2) (- x^{2} + 2 x)

Solution steps

\frac{d}{d x} ((2 x - x^{2})^{2} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} ((2 x - x^{2})^{2}) + \frac{d}{d x} (9)

\frac{d}{d x} ((2 x - x^{2})^{2}) = 2 (2 x - x^{2}) (2 - 2 x)

\frac{d}{d x} (9) = 0

= 2 (2 x - x^{2}) (2 - 2 x) + 0

Simplify

= 2 (- 2 x + 2) (- x^{2} + 2 x)

\int (x - 2) ln (x) d x

4 x^{2} + y^{2} = 25, (2, 3)

70 x^{- 5}

\int \frac{x ^{2}}{( a + b x ^{3} ) ^{2}} d x

x \to 0 + lim ((tan (7 x))^{x})

What is the derivative of (2x-x^2^2+9) ?
The derivative of (2x-x^2^2+9) is 2(-2x+2)(-x^2+2x)
What is the first derivative of (2x-x^2^2+9) ?
The first derivative of (2x-x^2^2+9) is 2(-2x+2)(-x^2+2x)