What is the derivative of f(x)=4cos(2x) ?

The derivative of f(x)=4cos(2x) is -8sin(2x)

What is the first derivative of f(x)=4cos(2x) ?

The first derivative of f(x)=4cos(2x) is -8sin(2x)

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derivative of

f (x) = 4 cos (2 x)

- 8 sin (2 x)

Solution steps

\frac{d}{d x} (4 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 4 (- sin (2 x) \cdot 2)

Simplify

= - 8 sin (2 x)

\frac{d}{d x} (\frac{3}{x - 5})

y = x^{2} + 8

x \to 0 + lim (cot (3 x))

\frac{\partial}{\partial y} (3 x y^{2})

What is the derivative of f(x)=4cos(2x) ?
The derivative of f(x)=4cos(2x) is -8sin(2x)
What is the first derivative of f(x)=4cos(2x) ?
The first derivative of f(x)=4cos(2x) is -8sin(2x)