What is (\partial)/(\partial y)(2x^2yz) ?

The answer to (\partial)/(\partial y)(2x^2yz) is 2x^2z

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(\partial)/(\partial y)(2x^2yz)

\frac{\partial}{\partial y} (2 x^{2} yz)

2 x^{2} z

Solution steps

\frac{\partial}{\partial y} (2 x^{2} yz)

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{2} z \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 2 x^{2} z \cdot 1

Simplify

= 2 x^{2} z

v \to 4 lim (\frac{v ^{2} - 6 v + 8}{2 v ^{2} - 8 v})

\frac{\partial}{\partial t} (r cos (t))

\frac{4 e ^{4 x}}{e ^{8} ( e ^{16} - 1 )}

\int \frac{2 x}{25 - x ^{2}} d x

e^{- \frac{t}{2}}

What is (\partial)/(\partial y)(2x^2yz) ?
The answer to (\partial)/(\partial y)(2x^2yz) is 2x^2z