What is the derivative of f(x)=(25x^3)/3+10x^2+4x-7 ?

The derivative of f(x)=(25x^3)/3+10x^2+4x-7 is 25x^2+20x+4

What is the first derivative of f(x)=(25x^3)/3+10x^2+4x-7 ?

The first derivative of f(x)=(25x^3)/3+10x^2+4x-7 is 25x^2+20x+4

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derivative of

f (x) = \frac{25 x ^{3}}{3} + 10 x^{2} + 4 x - 7

25 x^{2} + 20 x + 4

Solution steps

\frac{d}{d x} (\frac{25 x ^{3}}{3} + 10 x^{2} + 4 x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{25 x ^{3}}{3}) + \frac{d}{d x} (10 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (7)

\frac{d}{d x} (\frac{25 x ^{3}}{3}) = 25 x^{2}

\frac{d}{d x} (10 x^{2}) = 20 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= 25 x^{2} + 20 x + 4 - 0

Simplify

= 25 x^{2} + 20 x + 4

\int_{0}^{\frac{π}{2}} cos (θ) d θ

\frac{\partial}{\partial x} (x y^{- 1})

\int \frac{1}{6 y ^{2}} d y

\int_{a}^{b} x (b - x)^{2} d x

f (- 4) = 3 x + \frac{2}{x}

What is the derivative of f(x)=(25x^3)/3+10x^2+4x-7 ?
The derivative of f(x)=(25x^3)/3+10x^2+4x-7 is 25x^2+20x+4
What is the first derivative of f(x)=(25x^3)/3+10x^2+4x-7 ?
The first derivative of f(x)=(25x^3)/3+10x^2+4x-7 is 25x^2+20x+4