What is the derivative of 3/((1-x^2^4)) ?

The derivative of 3/((1-x^2^4)) is (24x)/((1-x^2)^5)

What is the first derivative of 3/((1-x^2^4)) ?

The first derivative of 3/((1-x^2^4)) is (24x)/((1-x^2)^5)

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\frac{d}{d x} (\frac{3}{( 1 - x ^{2} ) ^{4}})

\frac{24 x}{( 1 - x ^{2} ) ^{5}}

Solution steps

\frac{d}{d x} (\frac{3}{( 1 - x ^{2} ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{( 1 - x ^{2} ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((1 - x^{2})^{- 4})

Apply the chain rule:

- \frac{4}{( 1 - x ^{2} ) ^{5}} \frac{d}{d x} (1 - x^{2})

= - \frac{4}{( 1 - x ^{2} ) ^{5}} \frac{d}{d x} (1 - x^{2})

\frac{d}{d x} (1 - x^{2}) = - 2 x

= 3 (- \frac{4}{( 1 - x ^{2} ) ^{5}} (- 2 x))

Simplify

3 (- \frac{4}{( 1 - x ^{2} ) ^{5}} (- 2 x)) : \frac{24 x}{( 1 - x ^{2} ) ^{5}}

= \frac{24 x}{( 1 - x ^{2} ) ^{5}}

\frac{d}{d x} (cos^{4} (x) - sin^{4} (x))

k = 1 \sum \infty a (k - 1) x^{k}

\int \frac{1}{( 5 x + 1 )} d x

(t + 1)^{2} e^{- 2 t}

(y^{2} - x y) d x + (x^{2}) d y = 0

What is the derivative of 3/((1-x^2^4)) ?
The derivative of 3/((1-x^2^4)) is (24x)/((1-x^2)^5)
What is the first derivative of 3/((1-x^2^4)) ?
The first derivative of 3/((1-x^2^4)) is (24x)/((1-x^2)^5)