What is the derivative of x^5+1 ?

The derivative of x^5+1 is 5x^4

What is the first derivative of x^5+1 ?

The first derivative of x^5+1 is 5x^4

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\frac{d}{d x} (x^{5} + 1)

5 x^{4}

Solution steps

\frac{d}{d x} (x^{5} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{5}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (1) = 0

= 5 x^{4} + 0

Simplify

= 5 x^{4}

\int \frac{cot ( ln ( x ^{4} + 1 ) ) x ^{3}}{x ^{4} + 1} d x

\frac{( s ^{2} + 1 )}{s ( s - 1 ) ^{3}}

\frac{\partial}{\partial x} (e^{x y + 1})

\frac{( 5 x - 2 )}{( x + 1 )}, 4

\frac{d}{d x} ((2 x^{3} - 3) (sin (x) + 2))