What is the integral of (-e^{2-x}) ?

The integral of (-e^{2-x}) is e^{2-x}+C

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integral of (-e^{2-x})

\int (- e^{2 - x}) d x

e^{2 - x} + C

Solution steps

\int - e^{2 - x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{2 - x} d x

Apply u-substitution

: \int - e^{u} d u

= - \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= - (- e^{u})

Substitute back

u = 2 - x

= - (- e^{2 - x})

Simplify

= e^{2 - x}

Add a constant to the solution

= e^{2 - x} + C

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