What is the integral of (3x^2)/((169+x^2)^2) ?

The integral of (3x^2)/((169+x^2)^2) is (3(x^2arctan(x/(13))-13x+169arctan(x/(13))))/(26(169+x^2))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3x^2)/((169+x^2)^2)

\int \frac{3 x ^{2}}{( 169 + x ^{2} ) ^{2}} d x

\frac{3 ( x ^{2} arctan ( \frac{x}{13} ) - 13 x + 169 arctan ( \frac{x}{13} ) )}{26 ( 169 + x ^{2} )} + C

Solution steps

\int \frac{3 x ^{2}}{( 169 + x ^{2} ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x ^{2}}{( 169 + x ^{2} ) ^{2}} d x

Apply Integral Substitution

= 3 \cdot \int \frac{u ^{2}}{13 ( u ^{2} + 1 ) ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{13} \cdot \int \frac{u ^{2}}{( u ^{2} + 1 ) ^{2}} d u

Take the partial fraction of

\frac{u ^{2}}{( u ^{2} + 1 ) ^{2}} : \frac{1}{u ^{2} + 1} - \frac{1}{( u ^{2} + 1 ) ^{2}}

= 3 \cdot \frac{1}{13} \cdot \int \frac{1}{u ^{2} + 1} - \frac{1}{( u ^{2} + 1 ) ^{2}} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 3 \cdot \frac{1}{13} (\int \frac{1}{u ^{2} + 1} d u - \int \frac{1}{( u ^{2} + 1 ) ^{2}} d u)

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

\int \frac{1}{( u ^{2} + 1 ) ^{2}} d u = \frac{1}{2} (arctan (u) + \frac{u}{1 + u ^{2}})

= 3 \cdot \frac{1}{13} (arctan (u) - \frac{1}{2} (arctan (u) + \frac{u}{1 + u ^{2}}))

Substitute back

u = \frac{x}{13}

= 3 \cdot \frac{1}{13} (arctan (\frac{x}{13}) - \frac{1}{2} (arctan (\frac{x}{13}) + \frac{\frac{x}{13}}{1 + ( \frac{x}{13} ) ^{2}}))

Simplify

3 \cdot \frac{1}{13} (arctan (\frac{x}{13}) - \frac{1}{2} (arctan (\frac{x}{13}) + \frac{\frac{x}{13}}{1 + ( \frac{x}{13} ) ^{2}})) : \frac{3 ( x ^{2} arctan ( \frac{x}{13} ) - 13 x + 169 arctan ( \frac{x}{13} ) )}{26 ( 169 + x ^{2} )}

= \frac{3 ( x ^{2} arctan ( \frac{x}{13} ) - 13 x + 169 arctan ( \frac{x}{13} ) )}{26 ( 169 + x ^{2} )}

Add a constant to the solution

= \frac{3 ( x ^{2} arctan ( \frac{x}{13} ) - 13 x + 169 arctan ( \frac{x}{13} ) )}{26 ( 169 + x ^{2} )} + C

n = 1 \sum \infty \frac{4}{n + 1}

n = 0 \sum \infty n (\frac{4}{5})^{n}

\frac{\partial}{\partial x} (cos (2 x + 2 y))

n = 1 \sum \infty - \frac{3}{2 ^{n}}

\int \frac{x ^{2}}{13 - 4 x + x ^{2}} d x

What is the integral of (3x^2)/((169+x^2)^2) ?
The integral of (3x^2)/((169+x^2)^2) is (3(x^2arctan(x/(13))-13x+169arctan(x/(13))))/(26(169+x^2))+C