What is the derivative of sec(x-2cos(x)) ?

The derivative of sec(x-2cos(x)) is sec(x)tan(x)+2sin(x)

What is the first derivative of sec(x-2cos(x)) ?

The first derivative of sec(x-2cos(x)) is sec(x)tan(x)+2sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (sec (x) - 2 cos (x))

sec (x) tan (x) + 2 sin (x)

Solution steps

\frac{d}{d x} (sec (x) - 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sec (x)) - \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= sec (x) tan (x) - (- 2 sin (x))

Simplify

= sec (x) tan (x) + 2 sin (x)

\int 8 sin (t) d t

\frac{\partial}{\partial x} (3 x^{4} y^{5})

\frac{d}{d x} ((x^{2} + 1)^{5})

\int cos (x) - cos^{3} (x) d x

f (x) = 7 + x^{2}

What is the derivative of sec(x-2cos(x)) ?
The derivative of sec(x-2cos(x)) is sec(x)tan(x)+2sin(x)
What is the first derivative of sec(x-2cos(x)) ?
The first derivative of sec(x-2cos(x)) is sec(x)tan(x)+2sin(x)