What is the derivative of (x^2+1^5) ?

The derivative of (x^2+1^5) is 10x(x^2+1)^4

What is the first derivative of (x^2+1^5) ?

The first derivative of (x^2+1^5) is 10x(x^2+1)^4

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\frac{d}{d x} ((x^{2} + 1)^{5})

10 x (x^{2} + 1)^{4}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{5})

Apply the chain rule:

5 (x^{2} + 1)^{4} \frac{d}{d x} (x^{2} + 1)

= 5 (x^{2} + 1)^{4} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 5 (x^{2} + 1)^{4} \cdot 2 x

Simplify

= 10 x (x^{2} + 1)^{4}

\int cos (x) - cos^{3} (x) d x

f (x) = 7 + x^{2}

7 e^{7 e^{x} + x}

f (z) = 3 x + 2 z + 4 x z

f (x) = 12 x^{4} + 3 x^{3} + 5 x^{- 2} - 4

What is the derivative of (x^2+1^5) ?
The derivative of (x^2+1^5) is 10x(x^2+1)^4
What is the first derivative of (x^2+1^5) ?
The first derivative of (x^2+1^5) is 10x(x^2+1)^4