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Popular >

(dh)/(dt)=4-16t^2

Solution

\frac{d h}{d t} = 4 - 16 t^{2}

Solution

h = 4 t - \frac{16 t ^{3}}{3} + c_{1}

Solution steps

\frac{d h}{d t} = 4 - 16 t^{2}

Substitute

\frac{d h}{d t}

with

h^{'} (t)

h^{^{'}} (t) = 4 - 16 t^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

h = \int 4 - 16 t^{2} d t

\int 4 - 16 t^{2} d t = 4 t - \frac{16 t ^{3}}{3} + c_{1}

h = 4 t - \frac{16 t ^{3}}{3} + c_{1}

Popular Examples

derivative of g(x)=x^2+3x^3 derivative of

g (x) = x^{2} + 3 x^{3}

(dy)/(dx)(xy)=7

\frac{d y}{d x} (x y) = 7

derivative of f(x)=(x^2-7)/(16-x^2)derivative of

f (x) = \frac{x ^{2} - 7}{16 - x ^{2}}

integral of log_{a}(x)

\int lo g_{a} (x) d x

(\partial)/(\partial y)(xy^{1/2})

\frac{\partial}{\partial y} (x y^{\frac{1}{2}})

Frequently Asked Questions (FAQ)

What is the solution for (dh)/(dt)=4-16t^2 ?
The solution for (dh)/(dt)=4-16t^2 is h=4t-(16t^3)/3+c_{1}