What is (\partial)/(\partial x)(2y-x^2) ?

The answer to (\partial)/(\partial x)(2y-x^2) is -2x

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(\partial)/(\partial x)(2y-x^2)

\frac{\partial}{\partial x} (2 y - x^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (2 y - x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

\frac{d}{d x} (\frac{( x ^{2} - 5 x )}{x + 1})

\int \frac{x + 5}{5 - x} d x

\frac{d}{d x} ((5 x^{3} - 8)^{10})

x \to 6 - lim (5)

y^{^{''}} + y^{^{'}} - 2 y = 2 t, y (0) = 0, y^{^{'}} (0) = 1

What is (\partial)/(\partial x)(2y-x^2) ?
The answer to (\partial)/(\partial x)(2y-x^2) is -2x