What is the slope of x^{1/2}+y^{1/2}=4 ?

The slope of x^{1/2}+y^{1/2}=4 is -4/(x^{1/2)}+1

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slope of x^{1/2}+y^{1/2}=4

slope

x^{\frac{1}{2}} + y^{\frac{1}{2}} = 4

- \frac{4}{x ^{\frac{1}{2}}} + 1

Solution steps

x^{\frac{1}{2}} + y^{\frac{1}{2}} = 4

Isolate

y

for

x^{\frac{1}{2}} + y^{\frac{1}{2}} = 4 : y = 16 - 8 x^{\frac{1}{2}} + x

In order to find the slope of the function, take the derivative of

16 - 8 x^{\frac{1}{2}} + x

\frac{d}{d x} (16 - 8 x^{\frac{1}{2}} + x) = - \frac{4}{x ^{\frac{1}{2}}} + 1

- \frac{4}{x ^{\frac{1}{2}}} + 1

f (x) = arcsin (4 x)

f (x) = - 6 x^{2} - 10 x, at x = 1

\frac{t ^{2} + 1}{t ^{2} - 1}

y = x (2 x + 3)^{5}

\frac{\partial}{\partial x} (arcsin (x - y))

What is the slope of x^{1/2}+y^{1/2}=4 ?
The slope of x^{1/2}+y^{1/2}=4 is -4/(x^{1/2)}+1