What is area y=4cos(x),y=6-2cos(x),0<= x<= 2pi ?

The answer to area y=4cos(x),y=6-2cos(x),0<= x<= 2pi is 12pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=4cos(x),y=6-2cos(x),0<= x<= 2pi

area

y = 4 cos (x), y = 6 - 2 cos (x), 0 \leq x \leq 2 π

12 π

Decimal Notation

37.69911 \dots

Solution steps

Apply the area formula:

\int_{0}^{2 π} ∣ 4 cos (x) - (6 - 2 cos (x)) ∣ d x

Solve

\int_{0}^{2 π} ∣ 4 cos (x) - (6 - 2 cos (x)) ∣ d x : 12 π

The area is:

= 12 π

\frac{d y}{d x} = \frac{cos ( 8 x )}{e ^{8 y}}, y (0) = 1

f (x) = x, at x = 49

\frac{e ^{x}}{x}

\frac{d y}{d x} = 1 + \frac{2}{( y - x ) e ^{3 (y - x)}}

x \to 1 lim (ln (3) + e^{x})

What is area y=4cos(x),y=6-2cos(x),0<= x<= 2pi ?
The answer to area y=4cos(x),y=6-2cos(x),0<= x<= 2pi is 12pi