What is the limit as x approaches 1 of ln(3)+e^x ?

The limit as x approaches 1 of ln(3)+e^x is ln(3)+e

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limit as x approaches 1 of ln(3)+e^x

x \to 1 lim (ln (3) + e^{x})

ln (3) + e

Decimal Notation

3.81689 \dots

Solution steps

x \to 1 lim (ln (3) + e^{x})

Plug in the value

x = 1

= ln (3) + e^{1}

Simplify

= ln (3) + e

\frac{d}{d x} (ln (4 x - 2 y + 6))

y^{^{''}} + 9 y = 3 sin (2 x)

x \to 4 - lim (2)

y^{^{''}} + 2 y^{^{'}} = 8

y^{^{'}} = - \frac{y}{2000} 4, y (0) = 70

What is the limit as x approaches 1 of ln(3)+e^x ?
The limit as x approaches 1 of ln(3)+e^x is ln(3)+e