What is (\partial)/(\partial x)(2x^3y) ?

The answer to (\partial)/(\partial x)(2x^3y) is 6x^2y

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(\partial)/(\partial x)(2x^3y)

\frac{\partial}{\partial x} (2 x^{3} y)

6 x^{2} y

Solution steps

\frac{\partial}{\partial x} (2 x^{3} y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y \cdot 3 x^{3 - 1}

Simplify

= 6 x^{2} y

y^{^{'}} = - 2 y

f (x) = (x^{2} - 1)^{2}, (- 2, 9)

\frac{\partial}{\partial x} (y x^{y - 1})

\frac{6 x ^{2} + 8 x + 8}{x}

\frac{\partial}{\partial x} (3 sin^{2} (x))

What is (\partial)/(\partial x)(2x^3y) ?
The answer to (\partial)/(\partial x)(2x^3y) is 6x^2y