What is the solution for 7x^2y^{''}+15xy^'+y=0 ?

The solution for 7x^2y^{''}+15xy^'+y=0 is y=(c_{1}}{\sqrt[7]{x}}+\frac{c_{2})/x

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7x^2y^{''}+15xy^'+y=0

7 x^{2} y^{^{''}} + 15 x y^{^{'}} + y = 0

Solution steps

7 x^{2} y^{''} (x) + 15 x y^{'} (x) + y = 0

Solve linear ODE:

(x^{3} - 6 x^{2} + 2 x - 2)^{^{'}}

sin (x) + \frac{1}{2} cot (x)

y = \frac{ln ( x )}{1 + ln ( x )}

\frac{d}{d x} ((x^{3} + 5) (5 x^{2} - 5))

x y^{2} \frac{d y}{d x} = y^{3} - x^{3}, y (1) = 4

What is the solution for 7x^2y^{''}+15xy^'+y=0 ?
The solution for 7x^2y^{''}+15xy^'+y=0 is y=(c_{1}}{\sqrt[7]{x}}+\frac{c_{2})/x