What is the derivative of 9arctan(x) ?

The derivative of 9arctan(x) is 9/(x^2+1)

What is the first derivative of 9arctan(x) ?

The first derivative of 9arctan(x) is 9/(x^2+1)

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\frac{d}{d x} (9 arctan (x))

\frac{9}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (9 arctan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (arctan (x))

Apply the common derivative:

\frac{d}{d x} (arctan (x)) = \frac{1}{x ^{2} + 1}

= 9 \cdot \frac{1}{x ^{2} + 1}

Simplify

9 \cdot \frac{1}{x ^{2} + 1} : \frac{9}{x ^{2} + 1}

= \frac{9}{x ^{2} + 1}

f (x) = \frac{x ^{2} + 3 x - 2}{x}

x \to 0 lim (6 - \frac{1}{x ^{3}})

x \to 6 lim (- x^{2} + 3 x - 6)

\frac{\partial}{\partial x} (2 x y - 3 y cos (x) + 5 y^{2})

What is the derivative of 9arctan(x) ?
The derivative of 9arctan(x) is 9/(x^2+1)
What is the first derivative of 9arctan(x) ?
The first derivative of 9arctan(x) is 9/(x^2+1)