What is the derivative of g(u)=sqrt(2u)+sqrt(3u) ?

The derivative of g(u)=sqrt(2u)+sqrt(3u) is 1/(sqrt(2)\sqrt{u)}+(sqrt(3))/(2sqrt(u))

What is the first derivative of g(u)=sqrt(2u)+sqrt(3u) ?

The first derivative of g(u)=sqrt(2u)+sqrt(3u) is 1/(sqrt(2)\sqrt{u)}+(sqrt(3))/(2sqrt(u))

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derivative of

g (u) = 2 u + 3 u

\frac{1}{2 u} + \frac{3}{2 u}

Solution steps

\frac{d}{d u} (2 u + 3 u)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (2 u) + \frac{d}{d u} (3 u)

\frac{d}{d u} (2 u) = \frac{1}{2 u}

\frac{d}{d u} (3 u) = \frac{3}{2 u}

= \frac{1}{2 u} + \frac{3}{2 u}

- \frac{x}{1 - x ^{2}}

\int 1 + 36 x^{2} d x

\int (x \frac{e ^{- 2 x}}{2}) d x

y = sin (x) + tan (x)

cos ((π x)^{3})

What is the derivative of g(u)=sqrt(2u)+sqrt(3u) ?
The derivative of g(u)=sqrt(2u)+sqrt(3u) is 1/(sqrt(2)\sqrt{u)}+(sqrt(3))/(2sqrt(u))
What is the first derivative of g(u)=sqrt(2u)+sqrt(3u) ?
The first derivative of g(u)=sqrt(2u)+sqrt(3u) is 1/(sqrt(2)\sqrt{u)}+(sqrt(3))/(2sqrt(u))