What is the derivative of-x/(sqrt(1-x^2)) ?

The derivative of-x/(sqrt(1-x^2)) is -1/((1-x^2)sqrt(1-x^2))

What is the first derivative of-x/(sqrt(1-x^2)) ?

The first derivative of-x/(sqrt(1-x^2)) is -1/((1-x^2)sqrt(1-x^2))

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derivative of

- \frac{x}{1 - x ^{2}}

- \frac{1}{( 1 - x ^{2} ) 1 - x ^{2}}

Solution steps

\frac{d}{d x} (- \frac{x}{1 - x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{x}{1 - x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - \frac{\frac{d x}{d x} 1 - x ^{2} - \frac{d}{d x} ( 1 - x ^{2} ) x}{( 1 - x ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (1 - x^{2}) = - \frac{x}{1 - x ^{2}}

= - \frac{1 \cdot 1 - x ^{2} - ( - \frac{x}{1 - x ^{2}} ) x}{( 1 - x ^{2} ) ^{2}}

Simplify

- \frac{1 \cdot 1 - x ^{2} - ( - \frac{x}{1 - x ^{2}} ) x}{( 1 - x ^{2} ) ^{2}} : - \frac{1}{( 1 - x ^{2} ) 1 - x ^{2}}

= - \frac{1}{( 1 - x ^{2} ) 1 - x ^{2}}

\int 1 + 36 x^{2} d x

\int (x \frac{e ^{- 2 x}}{2}) d x

y = sin (x) + tan (x)

cos ((π x)^{3})

\frac{d}{d x} (ln (3 x^{2} - 2 x + 1))

What is the derivative of-x/(sqrt(1-x^2)) ?
The derivative of-x/(sqrt(1-x^2)) is -1/((1-x^2)sqrt(1-x^2))
What is the first derivative of-x/(sqrt(1-x^2)) ?
The first derivative of-x/(sqrt(1-x^2)) is -1/((1-x^2)sqrt(1-x^2))