What is (\partial)/(\partial x)(2x^3y^2) ?

The answer to (\partial)/(\partial x)(2x^3y^2) is 6x^2y^2

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(\partial)/(\partial x)(2x^3y^2)

\frac{\partial}{\partial x} (2 x^{3} y^{2})

6 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (2 x^{3} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y^{2} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y^{2} \cdot 3 x^{3 - 1}

Simplify

= 6 x^{2} y^{2}

x \to + 0 + lim (x^{x^{8}})

5 x y^{^{'}} - 2 y = - \frac{x ^{2}}{y ^{4}}

\int \frac{7}{4 - x ^{2}} d x

\frac{1}{( s - 1 ) ( s - 2 ) ( s - 3 )}

x \to 3 - lim (x 9 - x^{2})

What is (\partial)/(\partial x)(2x^3y^2) ?
The answer to (\partial)/(\partial x)(2x^3y^2) is 6x^2y^2