What is the tangent of 3/(5x+2),\at x=-1 ?

The tangent of 3/(5x+2),\at x=-1 is y=-5/3 x-8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 3/(5x+2),\at x=-1

tangent of

\frac{3}{5 x + 2}, at x = - 1

y = - \frac{5}{3} x - \frac{8}{3}

Solution steps

Find the tangent point:

(- 1, - 1)

Find the slope of

y = \frac{3}{5 x + 2} : \frac{d y}{d x} = - \frac{15}{( 5 x + 2 ) ^{2}}

Compute the slope of

y = \frac{3}{5 x + 2}

x = - 1 : m = - \frac{5}{3}

Find the line with slope m=

- \frac{5}{3}

and passing through

(- 1, - 1) : y = - \frac{5}{3} x - \frac{8}{3}

y = - \frac{5}{3} x - \frac{8}{3}

\int_{0}^{1} \frac{6 - x}{1 + x ^{2}} d x

x \to 2 lim (x + 2)

\int \frac{1}{( 361 + x ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{( x ^{2} + 1 )}{x ^{2} ( x + 1 ) ^{3}} d x

What is the tangent of 3/(5x+2),\at x=-1 ?
The tangent of 3/(5x+2),\at x=-1 is y=-5/3 x-8/3