What is the derivative of x^2\sqrt[3]{x^2} ?

The derivative of x^2\sqrt[3]{x^2} is 2x\sqrt[3]{x^2}+(2x^{5/3})/3

What is the first derivative of x^2\sqrt[3]{x^2} ?

The first derivative of x^2\sqrt[3]{x^2} is 2x\sqrt[3]{x^2}+(2x^{5/3})/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (x^{2}) = 2 x

\frac{2}{3 x ^{\frac{1}{3}}} x^{2} = \frac{2 x ^{\frac{5}{3}}}{3}

\int \frac{x}{x ^{2} + x} d x

\frac{d}{d x} (x^{2} \cdot e^{- x^{2}})

f (x) = - x^{2} - 2 x - 2, at x = - 3

\int \frac{I n ( x )}{x ^{2}} d x

\int \frac{x ^{3}}{x ^{2} + 5} d x

What is the derivative of x^2\sqrt[3]{x^2} ?
The derivative of x^2\sqrt[3]{x^2} is 2x\sqrt[3]{x^2}+(2x^{5/3})/3
What is the first derivative of x^2\sqrt[3]{x^2} ?
The first derivative of x^2\sqrt[3]{x^2} is 2x\sqrt[3]{x^2}+(2x^{5/3})/3