What is the limit as t approaches-1 of (e^t}{(\frac{e^t-6)/5)} ?

The limit as t approaches-1 of (e^t}{(\frac{e^t-6)/5)} is 5/(1-6e)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as t approaches-1 of (e^t}{(\frac{e^t-6)/5)}

t \to - 1 lim (\frac{e ^{t}}{( \frac{e ^{t} - 6}{5} )})

\frac{5}{1 - 6 e}

Decimal Notation

- 0.32659 \dots

Solution steps

t \to - 1 lim (\frac{e ^{t}}{\frac{e ^{t} - 6}{5}})

Plug in the value

t = - 1

= \frac{e ^{- 1}}{\frac{e ^{- 1} - 6}{5}}

Simplify

\frac{e ^{- 1}}{\frac{e ^{- 1} - 6}{5}} : \frac{5}{1 - 6 e}

= \frac{5}{1 - 6 e}

\int_{0}^{5} ∣ x - 2 ∣ d x

(1 + x)^{5}

\int_{0}^{9} \frac{1}{( x - 1 ) ^{\frac{1}{3}}} d x

f (x) = x^{3} - 2 x^{2} - 5 x + 6, at x = 2

\int_{0}^{3} 15 8 x + 1 d x

What is the limit as t approaches-1 of (e^t}{(\frac{e^t-6)/5)} ?
The limit as t approaches-1 of (e^t}{(\frac{e^t-6)/5)} is 5/(1-6e)