What is the solution for (dy)/(dx)+4xy=xe^{x^2} ?

The solution for (dy)/(dx)+4xy=xe^{x^2} is y=(e^{x^2})/6+(c_{1})/(e^{2x^2)}

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(dy)/(dx)+4xy=xe^{x^2}

\frac{d y}{d x} + 4 x y = x e^{x^{2}}

y = \frac{e ^{x^{2}}}{6} + \frac{c _{1}}{e ^{2 x^{2}}}

Solution steps

\frac{d y}{d x} + 4 x y = x e^{x^{2}}

Solve linear ODE:

y = \frac{e ^{x^{2}}}{6} + \frac{c _{1}}{e ^{2 x^{2}}}

y = \frac{e ^{x^{2}}}{6} + \frac{c _{1}}{e ^{2 x^{2}}}

x^{2} \cdot e^{x}

x \to - 5 lim (\frac{3 x + 8}{x + 5})

4 t

x \to 14 - lim (ln (14 - x))

y = e^{9 x} cos (π x), (0, 1)

What is the solution for (dy)/(dx)+4xy=xe^{x^2} ?
The solution for (dy)/(dx)+4xy=xe^{x^2} is y=(e^{x^2})/6+(c_{1})/(e^{2x^2)}