What is the solution for x(dy)/(dx)=y+(x^2-1)^2 ?

The solution for x(dy)/(dx)=y+(x^2-1)^2 is y=3x^4-2x^2+c_{1}x-(8x^4)/3-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x(dy)/(dx)=y+(x^2-1)^2

x \frac{d y}{d x} = y + (x^{2} - 1)^{2}

y = 3 x^{4} - 2 x^{2} + c_{1} x - \frac{8 x ^{4}}{3} - 1

Solution steps

x \frac{d y}{d x} = y + (x^{2} - 1)^{2}

Solve linear ODE:

y = 3 x^{4} - 2 x^{2} + c_{1} x - \frac{8 x ^{4}}{3} - 1

y = 3 x^{4} - 2 x^{2} + c_{1} x - \frac{8 x ^{4}}{3} - 1

x y^{^{'}} + y = - 9 x y^{2}, y (1) = - 2

x \to x + 2 lim (2 x^{2} + 3 x - 2)

(\frac{sin ( x )}{x})^{^{'}}

f (x) = ln (3 + 4 x)

\frac{S}{( ( S ^{2} + 9 ) ^{2} )}

What is the solution for x(dy)/(dx)=y+(x^2-1)^2 ?
The solution for x(dy)/(dx)=y+(x^2-1)^2 is y=3x^4-2x^2+c_{1}x-(8x^4)/3-1