What is the derivative of (x^3+3^3) ?

The derivative of (x^3+3^3) is 9x^2(x^3+3)^2

What is the first derivative of (x^3+3^3) ?

The first derivative of (x^3+3^3) is 9x^2(x^3+3)^2

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\frac{d}{d x} ((x^{3} + 3)^{3})

9 x^{2} (x^{3} + 3)^{2}

Solution steps

\frac{d}{d x} ((x^{3} + 3)^{3})

Apply the chain rule:

3 (x^{3} + 3)^{2} \frac{d}{d x} (x^{3} + 3)

= 3 (x^{3} + 3)^{2} \frac{d}{d x} (x^{3} + 3)

\frac{d}{d x} (x^{3} + 3) = 3 x^{2}

= 3 (x^{3} + 3)^{2} \cdot 3 x^{2}

Simplify

= 9 x^{2} (x^{3} + 3)^{2}

\int sin (x) (cos (x))^{5} d x

f (x) = 5 ln (4 x)

f (x) = \frac{x - 5}{( x + 3 ) ^{4}}

\int sin (x) sec^{10} (x) d x

\frac{8}{t ^{8}} - \frac{6}{t ^{6}} + \frac{3}{t}

What is the derivative of (x^3+3^3) ?
The derivative of (x^3+3^3) is 9x^2(x^3+3)^2
What is the first derivative of (x^3+3^3) ?
The first derivative of (x^3+3^3) is 9x^2(x^3+3)^2