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Popular >

derivative of \sqrt[5]{x}-2/x

Solution

Solution

\frac{x ^{2} + 10 x ^{\frac{4}{5}}}{5 x ^{\frac{14}{5}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= \frac{1}{5 x ^{\frac{4}{5}}} - (- \frac{2}{x ^{2}})

Simplify

\frac{1}{5 x ^{\frac{4}{5}}} - (- \frac{2}{x ^{2}}) : \frac{x ^{2} + 10 x ^{\frac{4}{5}}}{5 x ^{\frac{14}{5}}}

= \frac{x ^{2} + 10 x ^{\frac{4}{5}}}{5 x ^{\frac{14}{5}}}

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Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[5]{x}-2/x ?
The derivative of \sqrt[5]{x}-2/x is (x^2+10x^{4/5})/(5x^{14/5)}
What is the first derivative of \sqrt[5]{x}-2/x ?
The first derivative of \sqrt[5]{x}-2/x is (x^2+10x^{4/5})/(5x^{14/5)}