What is the derivative of sin(x-1) ?

The derivative of sin(x-1) is cos(x-1)

What is the first derivative of sin(x-1) ?

The first derivative of sin(x-1) is cos(x-1)

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\frac{d}{d x} (sin (x - 1))

cos (x - 1)

Solution steps

\frac{d}{d x} (sin (x - 1))

Apply the chain rule:

cos (x - 1) \frac{d}{d x} (x - 1)

= cos (x - 1) \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= cos (x - 1) \cdot 1

Simplify

= cos (x - 1)

\int cos (t) d t

\int (- 5 x^{6} - 3 x^{3} - 6 x + 5) d x

\int_{- 1}^{1} (e^{x}) - (x^{2} - 1) d x

2 y^{^{'}} + 9 y = 3

\int_{1}^{2} 7 \frac{ln ( x )}{x ^{2}} d x

What is the derivative of sin(x-1) ?
The derivative of sin(x-1) is cos(x-1)
What is the first derivative of sin(x-1) ?
The first derivative of sin(x-1) is cos(x-1)