What is the integral of (-5x^6-3x^3-6x+5) ?

The integral of (-5x^6-3x^3-6x+5) is -(5x^7)/7-(3x^4)/4-3x^2+5x+C

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integral of (-5x^6-3x^3-6x+5)

\int (- 5 x^{6} - 3 x^{3} - 6 x + 5) d x

- \frac{5 x ^{7}}{7} - \frac{3 x ^{4}}{4} - 3 x^{2} + 5 x + C

Solution steps

\int - 5 x^{6} - 3 x^{3} - 6 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 5 x^{6} d x - \int 3 x^{3} d x - \int 6 x d x + \int 5 d x

\int 5 x^{6} d x = \frac{5 x ^{7}}{7}

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int 6 x d x = 3 x^{2}

\int 5 d x = 5 x

= - \frac{5 x ^{7}}{7} - \frac{3 x ^{4}}{4} - 3 x^{2} + 5 x

Add a constant to the solution

= - \frac{5 x ^{7}}{7} - \frac{3 x ^{4}}{4} - 3 x^{2} + 5 x + C

\int_{- 1}^{1} (e^{x}) - (x^{2} - 1) d x

2 y^{^{'}} + 9 y = 3

\int_{1}^{2} 7 \frac{ln ( x )}{x ^{2}} d x

\int (e^{x^{2}})^{2} d x

\frac{d}{d x} ((3 x + 5)^{3})

What is the integral of (-5x^6-3x^3-6x+5) ?
The integral of (-5x^6-3x^3-6x+5) is -(5x^7)/7-(3x^4)/4-3x^2+5x+C