What is the solution for (dy)/(dx)=(xy)/(x^2+4),y(0)=6 ?

The solution for (dy)/(dx)=(xy)/(x^2+4),y(0)=6 is y=(x^2+4)^{1/2}*3

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(dy)/(dx)=(xy)/(x^2+4),y(0)=6

\frac{d y}{d x} = \frac{x y}{x ^{2} + 4}, y (0) = 6

y = (x^{2} + 4)^{\frac{1}{2}} \cdot 3

Solution steps

\frac{d y}{d x} = \frac{x y}{x ^{2} + 4}

Solve separable ODE:

y = (x^{2} + 4)^{\frac{1}{2}} \cdot 3

y = (x^{2} + 4)^{\frac{1}{2}} \cdot 3

10, x, \frac{x ^{2}}{40}

\int 2 cos (- 4 x) + 1 d x

\frac{\partial}{\partial x} (x^{2} - 4 x y + 3 y^{2})

\frac{d}{d x} ((x^{3} + 4) e^{x})

(s^{- \frac{1}{2}} + 2 s) (7 - s^{- 1})

What is the solution for (dy)/(dx)=(xy)/(x^2+4),y(0)=6 ?
The solution for (dy)/(dx)=(xy)/(x^2+4),y(0)=6 is y=(x^2+4)^{1/2}*3