What is (\partial)/(\partial x)(x^2-4xy+3y^2) ?

The answer to (\partial)/(\partial x)(x^2-4xy+3y^2) is 2x-4y

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(\partial)/(\partial x)(x^2-4xy+3y^2)

\frac{\partial}{\partial x} (x^{2} - 4 x y + 3 y^{2})

2 x - 4 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 4 x y + 3 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (4 x y) + \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 x y) = 4 y

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 2 x - 4 y + 0

Simplify

= 2 x - 4 y

\frac{d}{d x} ((x^{3} + 4) e^{x})

(s^{- \frac{1}{2}} + 2 s) (7 - s^{- 1})

f (x) = \frac{6}{5 x + 3}

\int_{0}^{2 π} e^{i x} d x

\frac{2 x}{x + 1}, at x = 1

What is (\partial)/(\partial x)(x^2-4xy+3y^2) ?
The answer to (\partial)/(\partial x)(x^2-4xy+3y^2) is 2x-4y