What is the tangent of f(x)= 2/x ?

The tangent of f(x)= 2/x is y=-2/(a_{0)^2}x+4/(a_{0)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 2/x

tangent of

f (x) = \frac{2}{x}

y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0}})

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

x = a_{0} : m = - \frac{2}{a _{0}^{2}}

Find the line with slope m=

- \frac{2}{a _{0}^{2}}

and passing through

(a_{0}, \frac{2}{a _{0}}) : y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

y = - \frac{2}{a _{0}^{2}} x + \frac{4}{a _{0}}

e^{π}

\frac{\partial}{\partial y} (4 x - 2 y)

\int 4 + \frac{1}{x} d x

\frac{d}{d x} (20 x - \frac{1}{2} \cdot 9.8 \cdot x^{2})

What is the tangent of f(x)= 2/x ?
The tangent of f(x)= 2/x is y=-2/(a_{0)^2}x+4/(a_{0)}