What is the derivative of (ln^2(x)/x) ?

The derivative of (ln^2(x)/x) is (2ln(x)-ln^2(x))/(x^2)

What is the first derivative of (ln^2(x)/x) ?

The first derivative of (ln^2(x)/x) is (2ln(x)-ln^2(x))/(x^2)

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\frac{d}{d x} (\frac{ln ^{2} ( x )}{x})

\frac{2 ln ( x ) - ln ^{2} ( x )}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{ln ^{2} ( x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( ln ^{2} ( x ) ) x - \frac{d x}{d x} ln ^{2} ( x )}{x ^{2}}

\frac{d}{d x} (ln^{2} (x)) = \frac{2 ln ( x )}{x}

\frac{d x}{d x} = 1

= \frac{\frac{2 l n ( x )}{x} x - 1 \cdot ln ^{2} ( x )}{x ^{2}}

Simplify

\frac{\frac{2 l n ( x )}{x} x - 1 \cdot ln ^{2} ( x )}{x ^{2}} : \frac{2 ln ( x ) - ln ^{2} ( x )}{x ^{2}}

= \frac{2 ln ( x ) - ln ^{2} ( x )}{x ^{2}}

x^{2} - 3 x y = 10, (1, - 3)

y^{^{''}} - y = 5 sin (2 t y) (0)

\frac{d}{d x} (sin (x) + sin^{2} (x))

(0, 4), (6, - 4)

What is the derivative of (ln^2(x)/x) ?
The derivative of (ln^2(x)/x) is (2ln(x)-ln^2(x))/(x^2)
What is the first derivative of (ln^2(x)/x) ?
The first derivative of (ln^2(x)/x) is (2ln(x)-ln^2(x))/(x^2)