What is the integral of 9cos(x) ?

The integral of 9cos(x) is 9sin(x)+C

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integral of 9cos(x)

\int 9 cos (x) d x

9 sin (x) + C

Solution steps

\int 9 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 9 sin (x)

Add a constant to the solution

= 9 sin (x) + C

\int (x cos (x^{2})) d x

\int (- x^{2} + 4) d x

y^{^{'}} = y cos (2 x)

\int_{1}^{\infty} x e^{- x^{2}} d x

y (2 x y + 1) d x - x d y = 0