What is the integral of 4cos(t) ?

The integral of 4cos(t) is 4sin(t)+C

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integral of 4cos(t)

\int 4 cos (t) d t

4 sin (t) + C

Solution steps

\int 4 cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= 4 sin (t)

Add a constant to the solution

= 4 sin (t) + C

\int cot^{2} (x) (1) d x

\int sin (4 x) sin (n x) d x

y^{^{''}} - 3 y^{^{'}} - 10 y = 0, y (0) = 1, y^{^{'}} (0) = 10

x \to \infty lim ((0.6)^{\frac{1}{x}})

\int 2 x (x^{2} + 4)^{4} d x