What is the tangent of f(x)=1+2sin(x),\at x=0 ?

The tangent of f(x)=1+2sin(x),\at x=0 is y=2x+1

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tangent of f(x)=1+2sin(x),\at x=0

tangent of

f (x) = 1 + 2 sin (x), at x = 0

y = 2 x + 1

Solution steps

Find the tangent point:

(0, 1)

Find the slope of

f (x) = 1 + 2 sin (x) : \frac{df ( x )}{d x} = 2 cos (x)

Compute the slope of

f (x) = 1 + 2 sin (x)

x = 0 : m = 2

Find the line with slope m=

2

and passing through

(0, 1) : y = 2 x + 1

y = 2 x + 1

y = x^{2} - 7 x + 7, (6, 1)

x \to π lim (e^{x})

\int x^{3} cos (h) x d x

\frac{d}{d x} (x^{2} csc (5 x))

\int 6 sin (3 x + 1) d x

What is the tangent of f(x)=1+2sin(x),\at x=0 ?
The tangent of f(x)=1+2sin(x),\at x=0 is y=2x+1