What is (\partial)/(\partial y)(y^2ln(x)) ?

The answer to (\partial)/(\partial y)(y^2ln(x)) is 2yln(x)

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(\partial)/(\partial y)(y^2ln(x))

\frac{\partial}{\partial y} (y^{2} ln (x))

2 y ln (x)

Solution steps

\frac{\partial}{\partial y} (y^{2} ln (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (x) \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= ln (x) \cdot 2 y^{2 - 1}

Simplify

= 2 y ln (x)

x \to 1 + lim (\frac{x - 2}{x - 1})

\frac{\partial}{\partial y} (x^{2} + y^{4})

\int cot (x) csc^{2} (x) d x

\int cot (\frac{x}{5}) d x

y = 3 - x^{2}, y = 7 - 5 x

What is (\partial)/(\partial y)(y^2ln(x)) ?
The answer to (\partial)/(\partial y)(y^2ln(x)) is 2yln(x)