What is (\partial)/(\partial y)(x^2+y^4) ?

The answer to (\partial)/(\partial y)(x^2+y^4) is 4y^3

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(\partial)/(\partial y)(x^2+y^4)

\frac{\partial}{\partial y} (x^{2} + y^{4})

4 y^{3}

Solution steps

\frac{\partial}{\partial y} (x^{2} + y^{4})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (y^{4})

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (y^{4}) = 4 y^{3}

= 0 + 4 y^{3}

Simplify

= 4 y^{3}

\int cot (x) csc^{2} (x) d x

\int cot (\frac{x}{5}) d x

y = 3 - x^{2}, y = 7 - 5 x

x \to 1 lim (\frac{x ^{2} - 9}{x + 3})

\frac{d}{d x} (∣ f (x) ∣)

What is (\partial)/(\partial y)(x^2+y^4) ?
The answer to (\partial)/(\partial y)(x^2+y^4) is 4y^3