What is (\partial)/(\partial x)(2xy+1) ?

The answer to (\partial)/(\partial x)(2xy+1) is 2y

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(\partial)/(\partial x)(2xy+1)

\frac{\partial}{\partial x} (2 x y + 1)

2 y

Solution steps

\frac{\partial}{\partial x} (2 x y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (1) = 0

= 2 y + 0

Simplify

= 2 y

\int x sec^{2} (d) x d x

\frac{d y}{d x}, y^{3} = x

\int e^{- 3 x} x d x

y = \frac{x + 1}{x}

x \to - 1 - lim (\frac{2}{x + 1})

What is (\partial)/(\partial x)(2xy+1) ?
The answer to (\partial)/(\partial x)(2xy+1) is 2y