What is the tangent of x^2+xy-y^2=-11,(1,4) ?

The tangent of x^2+xy-y^2=-11,(1,4) is y= 6/7 x+22/7

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tangent of x^2+xy-y^2=-11,(1,4)

tangent of

x^{2} + x y - y^{2} = - 11, (1, 4)

y = \frac{6}{7} x + \frac{22}{7}

Solution steps

Find the slope of

x^{2} + x y - y^{2} = - 11 : \frac{d y}{d x} = \frac{- 2 x - y}{x - 2 y}

Compute the slope of

x^{2} + x y - y^{2} = - 11

(1, 4) : m = \frac{6}{7}

Find the line with slope m=

\frac{6}{7}

and passing through

(1, 4) : y = \frac{6}{7} x + \frac{22}{7}

y = \frac{6}{7} x + \frac{22}{7}

\frac{d}{d x} (\frac{- 2 x ^{2}}{x ^{2} - 1})

2 cot (\frac{x}{8})

x \to - 2 lim (4)

\int \frac{1}{x ^{2} - 225} d x

\frac{\partial}{\partial s} (s + 2 t - u)

What is the tangent of x^2+xy-y^2=-11,(1,4) ?
The tangent of x^2+xy-y^2=-11,(1,4) is y= 6/7 x+22/7