What is (\partial)/(\partial x)(sin(7x-4y)) ?

The answer to (\partial)/(\partial x)(sin(7x-4y)) is cos(7x-4y)*7

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(\partial)/(\partial x)(sin(7x-4y))

\frac{\partial}{\partial x} (sin (7 x - 4 y))

cos (7 x - 4 y) \cdot 7

Solution steps

\frac{\partial}{\partial x} (sin (7 x - 4 y))

Treat

y

as a constant

Apply the chain rule:

cos (7 x - 4 y) \frac{\partial}{\partial x} (7 x - 4 y)

= cos (7 x - 4 y) \frac{\partial}{\partial x} (7 x - 4 y)

\frac{\partial}{\partial x} (7 x - 4 y) = 7

= cos (7 x - 4 y) \cdot 7

h \to 0 lim (\frac{( 1 + h ^{3} ) - 1}{h})

\frac{d}{d x} (\frac{e ^{x}}{1 - e ^{2 x}})

\int \frac{56}{1 - cos ( 8 x )} d x

(- 1, 2), (4, 3)

\frac{d ^{4}}{d x ^{4}} (16 e^{x^{2}})

What is (\partial)/(\partial x)(sin(7x-4y)) ?
The answer to (\partial)/(\partial x)(sin(7x-4y)) is cos(7x-4y)*7