What is the integral of cosh^2(x-1)sinh(x-1) ?

The integral of cosh^2(x-1)sinh(x-1) is (cosh^3(x-1))/3+C

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integral of cosh^2(x-1)sinh(x-1)

\int cosh^{2} (x - 1) sinh (x - 1) d x

\frac{cosh ^{3} ( x - 1 )}{3} + C

Solution steps

\int cosh^{2} (x - 1) sinh (x - 1) d x

Apply u-substitution

: \int cosh^{2} (u) sinh (u) d u

= \int cosh^{2} (u) sinh (u) d u

Apply u-substitution

: \int v^{2} d v

= \int v^{2} d v

Apply the Power Rule

: \frac{v ^{3}}{3}

= \frac{v ^{3}}{3}

Substitute back

= \frac{cosh ^{3} ( x - 1 )}{3}

Add a constant to the solution

= \frac{cosh ^{3} ( x - 1 )}{3} + C

x \to 0 lim (9 + x - 3)

x \to 0 lim ((x + e^{x})^{\frac{1}{x}})

\frac{d}{d x} (ln (x^{l n (x)}))

x \to 0 lim (1 + x^{2})

f (x) = x^{7} cos (x)

What is the integral of cosh^2(x-1)sinh(x-1) ?
The integral of cosh^2(x-1)sinh(x-1) is (cosh^3(x-1))/3+C