What is the integral from 0 to 1 of 3/(x^5) ?

The integral from 0 to 1 of 3/(x^5) is diverges

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integral from 0 to 1 of 3/(x^5)

\int_{0}^{1} \frac{3}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{3}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 3 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int (e^{x} + sin (x) + x) d x

x \to 0 lim (\frac{2 x}{x ^{2}})

x \to 0 lim (- cos (x))

\int 6 x - x^{2} d x

\frac{d}{d x} (3 x^{2} - 2 x - 8)

What is the integral from 0 to 1 of 3/(x^5) ?
The integral from 0 to 1 of 3/(x^5) is diverges