What is the derivative of 3x^2-2x-8 ?

The derivative of 3x^2-2x-8 is 6x-2

What is the first derivative of 3x^2-2x-8 ?

The first derivative of 3x^2-2x-8 is 6x-2

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\frac{d}{d x} (3 x^{2} - 2 x - 8)

6 x - 2

Solution steps

\frac{d}{d x} (3 x^{2} - 2 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (8)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 6 x - 2 - 0

Simplify

= 6 x - 2

y d x + (x - 8) d y = 0, y (9) = 36

\int \frac{1}{x ( 1 - x ) ^{2}} d x

(x + 1) \frac{d y}{d x} = - y + 10

y = x^{2} - 6, (- 2, - 2)

\int_{0}^{4} x d x

What is the derivative of 3x^2-2x-8 ?
The derivative of 3x^2-2x-8 is 6x-2
What is the first derivative of 3x^2-2x-8 ?
The first derivative of 3x^2-2x-8 is 6x-2