What is the tangent of y=x^2-6,(-2,-2) ?

The tangent of y=x^2-6,(-2,-2) is y=-4x-10

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tangent of y=x^2-6,(-2,-2)

tangent of

y = x^{2} - 6, (- 2, - 2)

y = - 4 x - 10

Solution steps

Find the slope of

y = x^{2} - 6 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} - 6

(- 2, - 2) : m = - 4

Find the line with slope m=

- 4

and passing through

(- 2, - 2) : y = - 4 x - 10

y = - 4 x - 10

\int_{0}^{4} x d x

\int 5 tan^{3} (sin (x)) cos (x) d x

- x^{2}, [0, 2]

\frac{\partial}{\partial x} (tan (x^{2}))

\frac{\partial}{\partial x} (x + t)

What is the tangent of y=x^2-6,(-2,-2) ?
The tangent of y=x^2-6,(-2,-2) is y=-4x-10