What is the integral from 0 to 4 of sqrt(x) ?

The integral from 0 to 4 of sqrt(x) is 16/3

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integral from 0 to 4 of sqrt(x)

\int_{0}^{4} x d x

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

\int_{0}^{4} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

\int 5 tan^{3} (sin (x)) cos (x) d x

- x^{2}, [0, 2]

\frac{\partial}{\partial x} (tan (x^{2}))

\frac{\partial}{\partial x} (x + t)

\frac{d y}{d x} + 3 y = 40, y (1) = 70

What is the integral from 0 to 4 of sqrt(x) ?
The integral from 0 to 4 of sqrt(x) is 16/3