What is the solution for (dy)/(dx)=xe^{x-2y} ?

The solution for (dy)/(dx)=xe^{x-2y} is y=(ln(2e^xx-2e^x+c_{1}))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=xe^{x-2y}

\frac{d y}{d x} = x e^{x - 2 y}

y = \frac{ln ( 2 e ^{x} x - 2 e ^{x} + c _{1} )}{2}

Solution steps

\frac{d y}{d x} = x e^{x - 2 y}

Solve separable ODE:

y = \frac{ln ( 2 e ^{x} x - 2 e ^{x} + c _{1} )}{2}

y = \frac{ln ( 2 e ^{x} x - 2 e ^{x} + c _{1} )}{2}

\int_{1}^{2} (x^{3} + \frac{1}{4 x ^{3}}) d x

\frac{d y}{d x} - \frac{2}{3 x} y + \frac{x ^{2} + 2}{3} y^{4} = 0

\int x \cdot ln (2 x) d x

y^{^{'}} = y (1 - 0.0004 y)

x = 4 y^{2}, x = 8 + 2 y^{2}

What is the solution for (dy)/(dx)=xe^{x-2y} ?
The solution for (dy)/(dx)=xe^{x-2y} is y=(ln(2e^xx-2e^x+c_{1}))/2