What is area y=2(x-2)^2-15,y=-(x+2)^2+1 ?

The answer to area y=2(x-2)^2-15,y=-(x+2)^2+1 is 256/27

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area y=2(x-2)^2-15,y=-(x+2)^2+1

area

y = 2 (x - 2)^{2} - 15, y = - (x + 2)^{2} + 1

\frac{256}{27}

Decimal Notation

9.48148 \dots

Solution steps

Apply the area formula:

\int_{- \frac{2}{3}}^{2} 2 (x - 2)^{2} - 15 - (- (x + 2)^{2} + 1) d x

Solve

\int_{- \frac{2}{3}}^{2} 2 (x - 2)^{2} - 15 - (- (x + 2)^{2} + 1) d x : \frac{256}{27}

The area is:

= \frac{256}{27}

\frac{\partial}{\partial x} (x + y + x^{3} y^{2})

\int \frac{1}{x ( x ^{2} + x + 1 )} d x

\int 9 x^{5} e^{x} d x

\frac{1}{s ( s ^{2} + 200 )}

x^{e^{x}}

What is area y=2(x-2)^2-15,y=-(x+2)^2+1 ?
The answer to area y=2(x-2)^2-15,y=-(x+2)^2+1 is 256/27