What is the integral of 9x^5e^x ?

The integral of 9x^5e^x is 9(x^5e^x-5(x^4e^x-4(x^3e^x-3(x^2e^x-2(e^xx-e^x)))))+C

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integral of 9x^5e^x

\int 9 x^{5} e^{x} d x

9 (x^{5} e^{x} - 5 (x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x}))))) + C

Solution steps

\int 9 x^{5} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int x^{5} e^{x} d x

Apply Integration By Parts

: x^{5} e^{x} - \int 5 x^{4} e^{x} d x

= 9 (x^{5} e^{x} - \int 5 x^{4} e^{x} d x)

\int 5 x^{4} e^{x} d x = 5 (x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x}))))

= 9 (x^{5} e^{x} - 5 (x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x})))))

Add a constant to the solution

= 9 (x^{5} e^{x} - 5 (x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x}))))) + C

\frac{1}{s ( s ^{2} + 200 )}

x^{e^{x}}

\frac{d}{d x} (2 x^{3} - 21 x^{2} + 60 x)

\int \frac{1}{4 - 25 x ^{2}} d x

\int_{0}^{1} \frac{x}{x ^{2} + 9} d x

What is the integral of 9x^5e^x ?
The integral of 9x^5e^x is 9(x^5e^x-5(x^4e^x-4(x^3e^x-3(x^2e^x-2(e^xx-e^x)))))+C